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[tex3]\sqrt[m]{(1+x)^2}-\sqrt[m]{(1-x)^2}=\sqrt[m]{1-x^2}[/tex3]
[tex3]\sqrt[m]{1-x^2}[/tex3]
[tex3]\left(1-x^2\right)=(1-x) \cdot (1+x)[/tex3]
[tex3]\sqrt[m]{\frac{\left(1+x\right)^2}{(1-x^2)}}-\sqrt[m]{\frac{\left(1-x\right)^2}{(1-x^2)}}=\sqrt[m]{\frac{(1-x^2)}{(1-x^2) }}[/tex3]
[tex3]\sqrt[m]{\frac{\left(1+x\right)\cdot \left(1+x\right)}{(1-x) \cdot (1+x))}}-\sqrt[m]{\frac{\left(1-x\right)\cdot \left(1-x\right)}{(1-x) \cdot (1+x))}}=\sqrt[m]{\frac{(1-x)\cdot (1+x)}{(1-x) \cdot(1+x)}}[/tex3]
[tex3]\sqrt[m]{\frac{1+x}{1-x}}-\sqrt[m]{\frac{1-x}{1+x}}=1[/tex3]
[tex3]\sqrt[m]{\frac{1+x}{1-x}}-\sqrt[m]{\left(\frac{1+x}{1-x}\right)^{-1}}=1[/tex3]
[tex3]\sqrt[m]{\frac{1+x}{1-x}}=k[/tex3]
[tex3]k-k^{-1}=1[/tex3]
[tex3]k-\frac{1}{k}=1[/tex3]
[tex3]k^2-k-1=0[/tex3]
[tex3]k=\frac{1+\sqrt5}{2}[/tex3]
[tex3]\frac{1-\sqrt5}{2}[/tex3]
[tex3]k[/tex3]
[tex3]m[/tex3]
[tex3]\sqrt[m]{\frac{1+x}{1-x}}=\frac{1+\sqrt5}{2}[/tex3]
[tex3]\frac{1+x}{1-x}=\left(\frac{1+\sqrt5}{2}\right)^m[/tex3]
[tex3]2^m+x \cdot 2^m=\left(1+\sqrt5\right)^m-x \cdot \left(1+\sqrt5\right)^m[/tex3]
[tex3]x \cdot 2^m+x \cdot \left(1+\sqrt5\right)^m=\left(1+\sqrt5\right)^m-2^m[/tex3]
[tex3]x \cdot \left[2^m+\left(1+\sqrt5\right)^m\right]=\left(1+\sqrt5\right)^m-2^m[/tex3]
[tex3]x=\frac{\left(1+\sqrt5\right)^m-2^m}{2^m+\left(1+\sqrt5\right)^m}[/tex3]