Resposta
Resp:
[tex3]-\frac{\sqrt{3}}{2}+\frac{1}{2}i,\,\,-\frac{\sqrt{3}}{2}-\frac{1}{2}i,\,\,-i,\,\,\frac{\sqrt{3}}{2}-\frac{1}{2}i,\,\,\frac{\sqrt{3}}{2}+\frac{1}{2}i ,\,\,\frac{\sqrt{3}}{2}-\frac{1}{2}i[/tex3]
Moderador: [ Moderadores TTB ]
[tex3]z = -1[/tex3] ; [tex3]z = cos 270 + isen270[/tex3]l3on4rd0 escreveu:Calcular [tex3]\sqrt[6]{-1}[/tex3]Resposta
Resp:
[tex3]-\frac{\sqrt{3}}{2}+\frac{1}{2}i,\,\,-\frac{\sqrt{3}}{2}-\frac{1}{2}i,\,\,-i,\,\,\frac{\sqrt{3}}{2}-\frac{1}{2}i,\,\,\frac{\sqrt{3}}{2}+\frac{1}{2}i ,\,\,\frac{\sqrt{3}}{2}-\frac{1}{2}i[/tex3]