A) [tex3]\frac{-cos2x}{2}+\frac{cos4x}{4}+c[/tex3]
B) [tex3]-cos2x-\frac{sen^22x}{2}+c[/tex3]
C) [tex3]-\frac{4cos^3x}{3}+c[/tex3]
D) [tex3]-\frac{3}{2}cos2x+c[/tex3]
E) [tex3]-cos2x-\frac{cos4x}{4}+c[/tex3]
Resposta
GAB:E
Moderador: [ Moderadores TTB ]