Calcule a integral :
[tex3]\int (x^\frac{3}{2}-2x^\frac{2}{8}+5\sqrt{x}-3)dx[/tex3]
Ensino Superior ⇒ Calculo de integrais Tópico resolvido
Moderador: [ Moderadores TTB ]
Jul 2020
03
16:54
Re: Calculo de integrais
[tex3]\int \left(x^\frac{3}{2}-2x^\frac{2}{8}+5\sqrt{x}-3\right)dx[/tex3]
[tex3]\int x^n=\frac{x^{n+1}}{n+1}[/tex3]
[tex3]\int[f(x)+g(x)]dx=\int f(x)dx+\int g(x)dx[/tex3]
[tex3]\int \left(x^\frac{3}{2}-2x^\frac{2}{8}+5\sqrt{x}-3\right)dx[/tex3]
[tex3]\int x^\frac{3}{2}dx-\int 2x^\frac{2}{8}dx+\int 5\sqrt{x}dx-\int 3dx[/tex3]
[tex3]\int x^\frac{3}{2}dx-2\int x^\frac{2}{8}dx+5\int \sqrt{x}dx-3\int dx[/tex3]
[tex3]\int x^\frac{3}{2}dx-2\int x^\frac{2}{8}dx+5\int x^{1\over2}dx-3\int dx[/tex3]
[tex3]\frac{x^{\frac{3}{2}+1}}{\frac{3}{2}+1}-2\frac{x^{\frac{2}{8}+1}}{\frac{2}{8}+1}+5\frac{x^{{1\over2}+1}}{{1\over2}+1}-3x+C[/tex3]
[tex3]\int (x^\frac{3}{2}-2x^\frac{2}{8}+5\sqrt{x}-3)dx=\frac{2x^{\frac{5}{2}}}{5}-\frac{8x^{\frac{5}{4}}}{5}+\frac{10x^{{3\over2}}}{3}-3x+C[/tex3]
[tex3]\int x^n=\frac{x^{n+1}}{n+1}[/tex3]
[tex3]\int[f(x)+g(x)]dx=\int f(x)dx+\int g(x)dx[/tex3]
[tex3]\int \left(x^\frac{3}{2}-2x^\frac{2}{8}+5\sqrt{x}-3\right)dx[/tex3]
[tex3]\int x^\frac{3}{2}dx-\int 2x^\frac{2}{8}dx+\int 5\sqrt{x}dx-\int 3dx[/tex3]
[tex3]\int x^\frac{3}{2}dx-2\int x^\frac{2}{8}dx+5\int \sqrt{x}dx-3\int dx[/tex3]
[tex3]\int x^\frac{3}{2}dx-2\int x^\frac{2}{8}dx+5\int x^{1\over2}dx-3\int dx[/tex3]
[tex3]\frac{x^{\frac{3}{2}+1}}{\frac{3}{2}+1}-2\frac{x^{\frac{2}{8}+1}}{\frac{2}{8}+1}+5\frac{x^{{1\over2}+1}}{{1\over2}+1}-3x+C[/tex3]
[tex3]\int (x^\frac{3}{2}-2x^\frac{2}{8}+5\sqrt{x}-3)dx=\frac{2x^{\frac{5}{2}}}{5}-\frac{8x^{\frac{5}{4}}}{5}+\frac{10x^{{3\over2}}}{3}-3x+C[/tex3]
[tex3]\color{YellowOrange}\textbf{Não importa o quanto se esforce ou evolua, você sempre estará abaixo do Sol}[/tex3]
[tex3]\textbf{Escanor}[/tex3]
[tex3]\textbf{Escanor}[/tex3]
-
- Tópicos Semelhantes
- Respostas
- Exibições
- Última msg
