g) [tex3]g(x) = \frac{2\sqrt{x}−7x^4}{8x^7−2^x}[/tex3]
Resposta
[tex3]g'(x)=\frac{\left(\:\frac{1}{\sqrt{x}}−28x^3\right)\left(8x^7−2x\right)−\left(2\sqrt{x}−7x^4\right)\left(56x^6−ln\left(2\right)2^x\right)}{\left(8x7−2^x\right)^2}[/tex3]
Moderador: [ Moderadores TTB ]