Integral
Enviado: Ter 13 Fev, 2018 16:29
Calcular a [tex3]\int\limits_{}^{}dx(tanx) ^{4}[/tex3]
[tex3]\int\limits_{}^{}(sec^2x-1)^2dx[/tex3]
[tex3]\int\limits_{}^{}(sec^4x-2sec^2x+1)dx[/tex3]
[tex3]\int\limits_{}^{} sec^4x dx +(x-2tgx)[/tex3]
[tex3]\int\limits_{}^{}sec^2x*sec^2xdx[/tex3]
[tex3]\int\limits_{}^{}(1+tgx^2x)*sec^2xdx[/tex3]
[tex3]\int\limits_{}^{}tg^2x*sec^2xdx+\int\limits_{}^{}sec^2xdx=\frac{tg^3x}{3}+tgx[/tex3]
[tex3]\frac{tg^3x}{3}-tgx+x+c=\int\limits_{}^{}(sec^2x-1)^2dx[/tex3]
Agora está mais "enxergável"