Ensino Fundamental ⇒ O algebrista Cápitulo 8 questão 18 Tópico resolvido

[bê1]

Resolver a equação:
(x-1)/4 - 1/8 ((x-5)/4 - (14 - 2x)/5) = (x-9)/2 - 7/8

Resposta

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R: x=17

[petras]

bê1,

[tex3] \frac{(x-1)} {4} - \frac{1}{8} [ { \frac{(x-5)}{4} } - (\frac{14 - 2x}{5})] = \frac{x-9}{2} - \frac{7}{8}\\
\frac{x-1}{4} -\frac{x-9}{2}+\frac{7}{8} = \frac{1}{8}[\frac{5x-25-56+8x]}{20}\\
\frac{2x-2-4x+36+7}{8} = \frac{13x-81}{160}\\
\frac{-2x+41}{8}=\frac{13x-81}{160} \implies 53x = 901\\
\therefore \boxed{x =17}


[/tex3]

Código: Selecionar tudoSHIFT+Click na eq = ZOOM

[tex3] \frac{(x-1)} {4} - \frac{1}{8} [ { \frac{(x-5)}{4} } - (\frac{14 - 2x}{5})] = \frac{x-9}{2} - \frac{7}{8}\\
\frac{x-1}{4} -\frac{x-9}{2}+\frac{7}{8} = \frac{1}{8}[\frac{5x-25-56+8x]}{20}\\
\frac{2x-2-4x+36+7}{8} = \frac{13x-81}{160}\\
\frac{-2x+41}{8}=\frac{13x-81}{160} \implies 53x = 901\\
\therefore \boxed{x =17}


[/tex3]