Ensino Fundamental ⇒ O algebrista Cápitulo 7 questão 34 Tópico resolvido

[bê1]

simplifique (2x² -5x +3)/(3x² + x -4) vezes (2x² + 3x -9)^(1/2)/(3x² +13x +12)^(1/2)

Resposta

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r:sqrt(2x-3)/(3x+4)

[petras]

Enunciado deve ter erro...substituindo por exemplo x=2
[tex3]\frac{2(2^2) -5.2 +3} {3(2^2) + 2 -4} . \left ( \frac{2(2^2) + 3.2 -9}{3(2^2) +13.2 +12}\right)^\frac{1}{2}\\
\frac{1}{10}. \left ( \frac{5}{50}\right)^\frac{1}{2} = \boxed{\frac{1}{10}\sqrt{\frac{1}{10}}}(I)\\
\sqrt{\frac{2(2)-3}{(3(2)+4)}}=\boxed{\sqrt{\frac{1}{10}}}(II)\\
\therefore (I) \neq(II)


[/tex3]

Código: Selecionar tudoSHIFT+Click na eq = ZOOM

[tex3]\frac{2(2^2) -5.2 +3} {3(2^2) + 2 -4} . \left ( \frac{2(2^2) + 3.2 -9}{3(2^2) +13.2 +12}\right)^\frac{1}{2}\\
\frac{1}{10}. \left ( \frac{5}{50}\right)^\frac{1}{2} = \boxed{\frac{1}{10}\sqrt{\frac{1}{10}}}(I)\\
\sqrt{\frac{2(2)-3}{(3(2)+4)}}=\boxed{\sqrt{\frac{1}{10}}}(II)\\
\therefore (I) \neq(II)


[/tex3]