[tex3]\angle ABD=\theta[/tex3]
[tex3]\angle BAC=\alpha[/tex3]
[tex3]\angle ACD=\beta[/tex3]
[tex3]\angle ABC=90^\circ[/tex3]
[tex3]\angle ADB=90^\circ[/tex3]
[tex3]BC=DC[/tex3]
Calcular [tex3]H=\cotg(\alpha) \cdot \cotg(\beta)[/tex3] , se [tex3]\theta = 15^\circ[/tex3] .
a) [tex3]10+5\sqrt{3}[/tex3]
b) [tex3]10+6\sqrt{3}[/tex3]
c) [tex3]10+4\sqrt{3}[/tex3]
d) [tex3]10+8\sqrt{3}[/tex3]
e) [tex3]10+7\sqrt{3}[/tex3]
Resposta
c