k)[tex3]0,008^{x}<\sqrt[3]{25} [/tex3]
Resposta
x<[tex3]\frac{-2}{9}[/tex3]
[tex3]0,008^{x}>\sqrt[3]{25} [/tex3]
[tex3]8^{-3x}>5^{\frac{2}{3}} [/tex3]
[tex3]\frac{1}{8}^{3x}>5^{\frac{2}{3}}[/tex3]
[tex3]0,125^{3x}>5^{\frac{2}{3}}[/tex3]
[tex3]0,5^{9x}>5^{\frac{2}{3}}[/tex3]
[tex3]5^{-9x}>5^{\frac{2}{3}}\rightarrow -9x>\frac{2}{3}\rightarrow x<\frac{-2}{27}[/tex3]
O que estou fazendo de errado?