First post
Prove, por indução finita, que vale a desigualdade:
\frac{1}{2} . \frac{3}{4} . \frac{5}{6} ... \frac{2n-1}{2n} \leq \frac{1}{\sqrt[]{3n+1}} , \forall n \in \mathbb{N}
Última msg
\frac{1}{2}\cdot\frac{3}{4}\cdot\frac{5}{6}\dots \frac{2n-1}{2n}\leq \frac{1}{\sqrt{3n+1}}~~~~~~~~~~\forall n,~n\geq1 \\\ \\\ \\\ \\\ \\\ \bf{P(1).~~ n=1} \\\ \\\ \frac{2-1}{2}\leq...