Sabendo que
[tex3]\begin{cases}
\frac{a^\sqrt{2}}{a}+\frac{b^\sqrt{2}}{b}+\frac{c^\sqrt{2}}{c}=\alpha \\
\frac{a^\sqrt{2}}{a^2}+\frac{b^\sqrt{2}}{b^2}+\frac{c^\sqrt{2}}{c^2}=\beta \\
\frac{a^\sqrt{2}}{a^3}+\frac{b^\sqrt{2}}{b^3}+\frac{c^\sqrt{2}}{c^3}=\theta
\end{cases}[/tex3]
e
[tex3]S=\left(\frac{a^\sqrt{2}+b^\sqrt{2}+c^\sqrt{2}+4\beta }{\alpha +\theta }\right)(a^{-2}+b^{-2}+c^{-2})[/tex3]
Então, a soma dos algarismos de S é igual a
a) 1
b) 2
c) 3
d) 4
e) 5
Resposta
E