Re: Termoquímica
Enviado: Qua 15 Mai, 2019 09:59
por LostWalker
Bom, eu n cheguei no gabarito, mas vou deixar aqui o equilíbrio e para quem for responder só copiar as equações, afinal fazer elas só perde tempo
[tex3]\,\,\,\,I\,\,\,.\,Na_{(s)}+\frac{1}{2}H_{2(g)}+C_{(s)}+\frac{3}{2}O_{2(g)}\rightarrow NaHCO_{3(s)}\,\,\,\,\,+948\,kJ\\
\,\,II\,.\,2\,Na_{(s)}+C_{(s)}+\frac{3}{2}O_{2(g)}\rightarrow Na_2CO_{3(s)}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+1\,131\,kJ\\
III.\,H_{2(g)}+\frac{1}{2}O_{2(g)}\rightarrow H_2O_{(g)}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+242\,kJ\\ {.} \\
\,IV\,.\,C_{(s)}+O_{2(g)}\rightarrow CO_{2(g)}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+394\,kJ[/tex3]
Para equilibrar de acordo com a equação
[tex3]I.\,\mbox{Inverte}[/tex3]
[tex3]II.\,\mbox{Divide por 2}[/tex3]
[tex3]III.\,\mbox{Divide por 2}[/tex3]
[tex3]IV.\,\mbox{Divide por 2}[/tex3]
Logo:
[tex3]\,\,\,\,I\,\,\,.\, NaHCO_{3(s)}\rightarrow Na_{(s)}+\frac{1}{2}H_{2(g)}+C_{(s)}+\frac{3}{2}O_{2(g)}\,\,\,\,\,-948\,kJ\\
\,\,II\,.\,\,Na_{(s)}+\frac{1}{2}C_{(s)}+\frac{3}{4}O_{2(g)}\rightarrow \frac{1}{2}Na_2CO_{3(s)}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+565.5\,kJ\\
III.\,\frac{1}{2}H_{2(g)}+\frac{1}{4}O_{2(g)}\rightarrow \frac{1}{2}H_2O_{(g)}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+121\,kJ\\
\,IV\,.\,\frac{1}{2}C_{(s)}+\frac{1}{2}O_{2(g)}\rightarrow \frac{1}{2}CO_{2(g)}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+197\,kJ[/tex3]
Somando Tudo:
[tex3]\,\,\,\,I\,\,\,.\, NaHCO_{3(s)}\rightarrow {\color{Red}\cancel{\color{Black}Na_{(s)}}}+{\color{JungleGreen}\cancel{\color{Black}\frac{1}{2}H_{2(g)}}}+{\color{YellowOrange}\cancel{\color{Black}C_{(s)}}}+{\color{Blue}\cancel{\color{Black}\frac{3}{2}O_{2(g)}}}\,\,\,\,\,-948\,kJ\\
\,\,II\,.\,\,{\color{Red}\cancel{\color{Black}Na_{(s)}}}+{\color{YellowOrange}\cancel{\color{Black}\frac{1}{2}C_{(s)}}}+{\color{Blue}\cancel{\color{Black}\frac{3}{4}O_{2(g)}}}\rightarrow \frac{1}{2}Na_2CO_{3(s)}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+565.5\,kJ\\
III.\,{\color{JungleGreen}\cancel{\color{Black}\frac{1}{2}H_{2(g)}}}+{\color{Blue}\cancel{\color{Black}\frac{1}{4}O_{2(g)}}}\rightarrow \frac{1}{2}H_2O_{(g)}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+121\,kJ\\
\,IV\,.\,{\color{YellowOrange}\cancel{\color{Black}\frac{1}{2}C_{(s)}}}+{\color{Blue}\cancel{\color{Black}\frac{1}{2}O_{2(g)}}}\rightarrow \frac{1}{2}CO_{2(g)}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+197\,kJ\\
[/tex3]
[tex3]\color{MidNightBlue}\boxed{\,\,S\,\,\,\,.\,NaHCO_{3(s)}\rightarrow \frac{1}{2}Na_2CO_{3(s)}+\frac{1}{2}H_2O_{(g)}+\frac{1}{2}CO_{2(g)}\,\,\,\,\,\,\,\,-64.5\,kJ}[/tex3]
Mas como eu disse, n sei chegar no Gabarito, só fiz para adiantar a explicação de quem for responder sem ter que descrever essa parte