[tex3]\Psi_E(x,t)=[C_+\exp(i\rho x/ \hbar)+C_-\exp (i\rho x/ \hbar )]\exp (-iEt/\hbar )[/tex3]
Resposta
[tex3]\rho =|C_+|^2+|C_-|^2+2Re(C_-^*C_+e^{2ikx})(k\equiv\rho / \hbar) ////
j=\left(|C_+|^2-|C_-|^2\right)v (v\equiv p/m)[/tex3]
j
Moderador: [ Moderadores TTB ]