First post
Resolva a desigualdade com 0 \leq x \leq 2pi
cosx+ \sqrt{3} senx > \sqrt{2}
Última msg
Letciia ,
(\div2)\implies \underbrace{\frac{cosx}{2}+\frac{\sqrt3}{2}senx}> \frac{\sqrt2}{2}\\
mas:sen (\frac{\pi}{6}+x)=sen\frac{\pi}{6}.cosx+senx.cos\frac{\pi}{6} =\underbrace{...