Resposta
[tex3]3 +A+\sqrt{3A}[/tex3]
Obrigadopetras escreveu: ↑23 Abr 2024, 19:52 Papiro8814,
[tex3]
\frac{A\sqrt{A}-3\sqrt{3}}{\sqrt{A}-\sqrt{3}}.\frac{\sqrt A+\sqrt3}{\sqrt A+\sqrt3}=\\
\frac{A^2+A\sqrt A\sqrt3 - 3\sqrt A \sqrt3-9}{A-3}=\\
\frac{(\cancel{A-3})(A+3)+(\sqrt A\sqrt3)(\cancel{A-3})}{\cancel{A-3}}\\
\therefore \boxed{A+3+\sqrt{3A}}
[/tex3]